**Hello. Please help me to solve the problem.**

Subject: decimals.

The sum of three numbers is 10 whole 4/10. The second number is 3 times smaller than the first, and at one whole 1/10 more than the third. Find these numbers.

Subject: decimals.

The sum of three numbers is 10 whole 4/10. The second number is 3 times smaller than the first, and at one whole 1/10 more than the third. Find these numbers.

Carefully read the conditions and form the equation. "The second number is 3 times smaller than the first" - this means that the first number is three times langer than the second. If the second number is denoted by X, then the first number is three X.

"The second number is (((3 times smaller than the first, and))) at one whole 1/10 more than the third" - means the third number is equal to X minus one whole 1/10.

Now write the sum of three numbers equate it to 10.4 and obtain the equation.

**3x + x + x - 1.1 = 10.4**

5x = 10.4 + 1.1

5x = 11.5

x = 11.5 / 5

x = 2.3

5x = 10.4 + 1.1

5x = 11.5

x = 11.5 / 5

x = 2.3

The second number is equal to

**2.3**

The first number is equal to

**2.3 * 3 = 6.9**

The third number is

**2.3-1.1 = 1.2**

Check the amount of received numbers

**6.9 + 2.3 + 1.2 = 10.4**

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